en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of 4/(s^2-9)

Solution

inverse

\frac{4}{s ^{2} - 9}

Solution

\frac{4 + 9 s}{s}, - \frac{4 + 9 s}{s}

Solution steps

y = \frac{4}{s ^{2} - 9}

Replace

s

with

y

s = \frac{4}{y ^{2} - 9}

Solve for

y, s = \frac{4}{y ^{2} - 9}

\frac{4 + 9 s}{s}, - \frac{4 + 9 s}{s}

Popular Examples

domain of sqrt(6x+1)domain

6 x + 1

critical f(x)=x^4-8x^2+2 critical points

f (x) = x^{4} - 8 x^{2} + 2

intercepts of f(x)=-(x+6)^2+6 intercepts

f (x) = - (x + 6)^{2} + 6

intercepts of y=(x+5)/(3x)intercepts

y = \frac{x + 5}{3 x}

range of sqrt((x-1)^2)range

(x - 1)^{2}

Frequently Asked Questions (FAQ)

What is the inverse of 4/(s^2-9) ?
The inverse of 4/(s^2-9) is sqrt((4+9s)/s),-sqrt((4+9s)/s)