What is the critical f(x,y)=4x^3-3x^2=3y^2 ?

The critical f(x,y)=4x^3-3x^2=3y^2 is y=0

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critical f(x,y)=4x^3-3x^2=3y^2

critical points

f (x, y) = 4 x^{3} - 3 x^{2} = 3 y^{2}

y = 0

Solution steps

3 y^{2}

Find where

f^{'} (y)

is equal to zero or undefined

y = 0

Identify critical points not in

f (y)

domain

Domain of

3 y^{2} : - \infty < y < \infty

All critical points are in domain

y = 0

f (x) = sin (x)

ln (X + 8)

- 2 cos (5 x)

x + 3 y = - 3

f (x) = 1.05 x

What is the critical f(x,y)=4x^3-3x^2=3y^2 ?
The critical f(x,y)=4x^3-3x^2=3y^2 is y=0