What is the range of f(x)=((x+1))/((x-2)) ?

The range of f(x)=((x+1))/((x-2)) is f(x) 1

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range of f(x)=((x+1))/((x-2))

range

f (x) = \frac{( x + 1 )}{( x - 2 )}

f (x) < 1 or f (x) > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{x + 1}{x - 2}

Inverse of

\frac{x + 1}{x - 2} : \frac{1 + 2 x}{x - 1}

\frac{1 + 2 x}{x - 1}

Find the domain of each inverse function

Domain of

\frac{1 + 2 x}{x - 1} : x < 1 or x > 1

Combine the intervals

f (x) < 1 or f (x) > 1

f (x) = \frac{x}{3}

y = - 2 x - 1

f (x) = 3 x + 1

2 x^{3} - 3 x^{2} - 36 x

f (x) = \frac{2}{x ^{2} + 3 x}

What is the range of f(x)=((x+1))/((x-2)) ?
The range of f(x)=((x+1))/((x-2)) is f(x)<1\lor f(x)>1