What is the line (-3, 1/32),(3,128) ?

The line (-3, 1/32),(3,128) is y= 1365/64 x+4097/64

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line (-3, 1/32),(3,128)

line

(- 3, \frac{1}{32}), (3, 128)

y = \frac{1365}{64} x + \frac{4097}{64}

Solution steps

Find the line

y = mx + b

passing through

(- 3, \frac{1}{32})

(3, 128)

Compute the slope

(- 3, \frac{1}{32}), (3, 128) : m = \frac{1365}{64}

Compute the

y

intercept:

b = \frac{4097}{64}

Construct the line equation

y = mx + b

where

m = \frac{1365}{64}

and

b = \frac{4097}{64}

y = \frac{1365}{64} x + \frac{4097}{64}

(x + 1)^{\frac{4}{5}}

2 x^{2} + 16 x - 9

f (x) = x^{3} - \frac{3}{2} x^{2}

What is the line (-3, 1/32),(3,128) ?
The line (-3, 1/32),(3,128) is y= 1365/64 x+4097/64