What is the range of f(x)=-sin(x-pi/3) ?

The range of f(x)=-sin(x-pi/3) is -1<= f(x)<= 1

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range of f(x)=-sin(x-pi/3)

range

f (x) = - sin (x - \frac{π}{3})

- 1 \leq f (x) \leq 1

Interval Notation

[- 1, 1]

Solution steps

The range of the basic

sin

function is

- 1 \leq sin (x - \frac{π}{3}) \leq 1

- 1 \leq sin (x - \frac{π}{3}) \leq 1

Multiply the edges of the range by:

- 1

- 1 \leq - sin (x - \frac{π}{3}) \leq 1

Therefore the range is

- 1 \leq f (x) \leq 1

f (x) = \frac{5}{3 x - 9}

f (x) = 17

2 x - y = 6, (- 7, - 8)

f (x) = (x + 4)^{2} - 9

What is the range of f(x)=-sin(x-pi/3) ?
The range of f(x)=-sin(x-pi/3) is -1<= f(x)<= 1