What is the domain of f(x)=\sqrt[4]{x^4-1} ?

The domain of f(x)=\sqrt[4]{x^4-1} is x = 1

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domain of f(x)=\sqrt[4]{x^4-1}

domain

x \leq - 1 or x \geq 1

Interval Notation

(- \infty, - 1] \cup [1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 1

The function domain

x \leq - 1 or x \geq 1

\frac{1}{x ^{2} - 6 x}

- 2 x + y = 4

\frac{x}{9 x - 8}

\frac{x ^{2} - 1}{1 + cos ^{2} ( x )}

f (x) = 3 x^{2} - 5

What is the domain of f(x)=\sqrt[4]{x^4-1} ?
The domain of f(x)=\sqrt[4]{x^4-1} is x<=-1\lor x>= 1