What is the shift f(x)=5sin(1/2 x+(3pi)/4) ?

The shift f(x)=5sin(1/2 x+(3pi)/4) is Phase:-(3pi)/2 , Vertical:0

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shift f(x)=5sin(1/2 x+(3pi)/4)

shift

f (x) = 5 sin (\frac{1}{2} x + \frac{3 π}{4})

Phase : - \frac{3 π}{2}, Vertical : 0

Solution steps

f (x) = 5 sin (\frac{1}{2} x + \frac{3 π}{4})

g (B x - C) = sin (\frac{1}{2} x + \frac{3 π}{4}), B = \frac{1}{2}, C = - \frac{3 π}{4}, D = 0

Therefore, the phase shift

\frac{C}{B}

\frac{- \frac{3 π}{4}}{\frac{1}{2}}

- \frac{3 π}{2}

The vertical shift

D

0

0

f (x) = \frac{1}{( x - 1 )}

(- 2, 6), (3, 3)

f (x) = \frac{x - 4}{x + 2}

f (x) = \frac{1}{2 x + 9}

f (x) = \frac{8 x}{x ^{2} - 1}

What is the shift f(x)=5sin(1/2 x+(3pi)/4) ?
The shift f(x)=5sin(1/2 x+(3pi)/4) is Phase:-(3pi)/2 , Vertical:0