What is the domain of f(x)=((x^2+1))/((x+3)) ?

The domain of f(x)=((x^2+1))/((x+3)) is x -3

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domain of f(x)=((x^2+1))/((x+3))

domain

f (x) = \frac{( x ^{2} + 1 )}{( x + 3 )}

x < - 3 or x > - 3

Interval Notation

(- \infty, - 3) \cup (- 3, \infty)

Solution steps

Find undefined (singularity) points:

x = - 3

The function domain

x < - 3 or x > - 3

f (x) = \frac{1}{3} x^{3} - 2

x^{2} - 6 x

3 + 2 sin (6 x + \frac{π}{4})

- 3 x^{2} + 3 x - 2

3 y + 6 x = 6

What is the domain of f(x)=((x^2+1))/((x+3)) ?
The domain of f(x)=((x^2+1))/((x+3)) is x<-3\lor x>-3