What is the critical 1/3 x^3+2x^2-2 ?

The critical 1/3 x^3+2x^2-2 is x=-4,x=0

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critical 1/3 x^3+2x^2-2

critical points

\frac{1}{3} x^{3} + 2 x^{2} - 2

x = - 4, x = 0

Solution steps

\frac{1}{3} x^{3} + 2 x^{2} - 2

Find where

f^{'} (x)

is equal to zero or undefined

x = - 4, x = 0

Identify critical points not in

f (x)

domain

Domain of

\frac{1}{3} x^{3} + 2 x^{2} - 2 : - \infty < x < \infty

All critical points are in domain

x = - 4, x = 0

x^{3} - 12 x^{2} + 36 x + 8

y = sin (x + 2)

y = \frac{1}{7} x + 9, (2, 5)

f (x) = 3 x - 4 y = - 8

f (x) = 1.5 (2)^{x}