What is the domain of sqrt(x^2-4x-5) ?

The domain of sqrt(x^2-4x-5) is x = 5

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domain of sqrt(x^2-4x-5)

domain

x^{2} - 4 x - 5

x \leq - 1 or x \geq 5

Interval Notation

(- \infty, - 1] \cup [5, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 5

The function domain

x \leq - 1 or x \geq 5

f (x) = \frac{3}{8} x - 4

3 y - 9 x = 21

f (x) = x + 2

(4, 3), (0, 3)

f (x) = 4 x^{3} - 7

What is the domain of sqrt(x^2-4x-5) ?
The domain of sqrt(x^2-4x-5) is x<=-1\lor x>= 5