What is the domain of f(x)=(x(x+1))/(x-1) ?

The domain of f(x)=(x(x+1))/(x-1) is x 1

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domain of f(x)=(x(x+1))/(x-1)

domain

f (x) = \frac{x ( x + 1 )}{x - 1}

x < 1 or x > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1

The function domain

x < 1 or x > 1

f (x) = 3 x - x^{2}

y = x^{3} + 2

f (x) = x (x - 2)

\frac{x - 4}{x + 4}

∣ x - 2 ∣ + 3

What is the domain of f(x)=(x(x+1))/(x-1) ?
The domain of f(x)=(x(x+1))/(x-1) is x<1\lor x>1