What is the domain of f(x)=(sqrt(x+9))/(x-5) ?

The domain of f(x)=(sqrt(x+9))/(x-5) is -9 5

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domain of f(x)=(sqrt(x+9))/(x-5)

domain

f (x) = \frac{x + 9}{x - 5}

- 9 \leq x < 5 or x > 5

Interval Notation

[- 9, 5) \cup (5, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 9

Find undefined (singularity) points:

x = 5

Combine real regions and undefined points for final function domain

- 9 \leq x < 5 or x > 5

6 x + 6

\frac{x ^{2} - 2 x - 15}{x ^{2} + 4 x}

f (x) = (x + 2)^{2}, x \geq - 2

y - 4 = \frac{1}{4} (x + 8)

x^{2} + 3 x + 3

What is the domain of f(x)=(sqrt(x+9))/(x-5) ?
The domain of f(x)=(sqrt(x+9))/(x-5) is -9<= x<5\lor x>5