en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme 2x^2-x-1

Solution

extreme points

2 x^{2} - x - 1

Solution

Minimum (\frac{1}{4}, - \frac{9}{8})

Solution steps

f^{'} (x) = 4 x - 1

Find intervals:

Decreasing

: - \infty < x < \frac{1}{4},

Increasing

: \frac{1}{4} < x < \infty

Plug

x = \frac{1}{4}

into

2 x^{2} - x - 1 : - \frac{9}{8}

Minimum (\frac{1}{4}, - \frac{9}{8})

Popular Examples

critical f(x)=e^xsqrt(x)critical points

f (x) = e^{x} x

asymptotes of f(x)=(x^2+4)/(x-2)asymptotes

f (x) = \frac{x ^{2} + 4}{x - 2}

inverse of-2x^2+6 inverse

- 2 x^{2} + 6

domain of arccos(e^x)domain

arccos (e^{x})

critical f(x)=(x-1)^{4/5}critical points

f (x) = (x - 1)^{\frac{4}{5}}

Frequently Asked Questions (FAQ)

What is the extreme 2x^2-x-1 ?
The extreme 2x^2-x-1 is Minimum(1/4 ,-9/8)