What is the domain of h(x)=sqrt(20x^2+7x-3) ?

The domain of h(x)=sqrt(20x^2+7x-3) is x = 1/4

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domain of h(x)=sqrt(20x^2+7x-3)

domain

h (x) = 20 x^{2} + 7 x - 3

x \leq - \frac{3}{5} or x \geq \frac{1}{4}

Interval Notation

(- \infty, - \frac{3}{5}] \cup [\frac{1}{4}, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - \frac{3}{5} or x \geq \frac{1}{4}

The function domain

x \leq - \frac{3}{5} or x \geq \frac{1}{4}

y = lo g_{3} (x) + 6

f (x) = - 2 x^{2} + 20 x - 50

\frac{( 3 x ^{2} - 2 x )}{( x ^{2} - x + 2 )}

lo g_{2} (\frac{1}{2 ^{- \frac{1}{2}}})

x^{2} y - 9 y - 3 x^{2} = 0

What is the domain of h(x)=sqrt(20x^2+7x-3) ?
The domain of h(x)=sqrt(20x^2+7x-3) is x<=-3/5 \lor x>= 1/4