What is the inverse of f(x)=3log_{2}(2x-8) ?

The inverse of f(x)=3log_{2}(2x-8) is (2^{x/3}+8)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=3log_{2}(2x-8)

inverse

f (x) = 3 lo g_{2} (2 x - 8)

\frac{2 ^{\frac{x}{3}} + 8}{2}

Solution steps

y = 3 lo g_{2} (2 x - 8)

Replace

x

with

y

x = 3 lo g_{2} (2 y - 8)

Solve for

y, x = 3 lo g_{2} (2 y - 8)

\frac{2 ^{\frac{x}{3}} + 8}{2}

f (x) = - tan (\frac{1}{4} x)

y = cos (3 x)

f (x) = (x - 4)^{2} - 1

f (x) = - 35 x + 5

f (x) = t 4 - t, t < 3

What is the inverse of f(x)=3log_{2}(2x-8) ?
The inverse of f(x)=3log_{2}(2x-8) is (2^{x/3}+8)/2