What is the critical f(x)=(x^2)/(4x+4) ?

The critical f(x)=(x^2)/(4x+4) is x=-2,x=0

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critical f(x)=(x^2)/(4x+4)

critical points

f (x) = \frac{x ^{2}}{4 x + 4}

x = - 2, x = 0

Solution steps

\frac{x ^{2}}{4 x + 4}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = 0, x = - 1

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2}}{4 x + 4} : x < - 1 or x > - 1

\frac{x ^{2}}{4 x + 4}

is not defined at

x = - 1

, therefore:

x = - 2, x = 0

f (x) = \frac{2 x ^{2} + 1}{3 x ^{2} - 5}

- 2 x^{2} + 12 x - 14

f (x) = 2 - 3 x^{2} - x^{3}

f (x) = x e^{- 3 x}

f (x) = 121 - x^{2}

What is the critical f(x)=(x^2)/(4x+4) ?
The critical f(x)=(x^2)/(4x+4) is x=-2,x=0