What is the domain of f(x)= x/(sqrt(16-x)) ?

The domain of f(x)= x/(sqrt(16-x)) is x<16

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domain of f(x)= x/(sqrt(16-x))

domain

f (x) = \frac{x}{16 - x}

x < 16

Interval Notation

(- \infty, 16)

Solution steps

Find non-negative values for radicals:

x \leq 16

Find undefined (singularity) points:

x = 16

Combine real regions and undefined points for final function domain

x < 16

f (x) = 9 - 8 x - 4 x^{2}

f (x) = - 16 x^{2} + 30 x + 3

f (x) = (x + 2)^{3} + 6

f (x) = 2 x - 2

y = 2 x^{2} - 8 x + 6

What is the domain of f(x)= x/(sqrt(16-x)) ?
The domain of f(x)= x/(sqrt(16-x)) is x<16