What is the inverse of f(x)={\sqrt[3]{x-1},x>= 1} ?

The inverse of f(x)={\sqrt[3]{x-1},x>= 1} is x^3+1

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inverse of f(x)={\sqrt[3]{x-1},x>= 1}

inverse

x^{3} + 1

Solution steps

Replace

x

with

y

Solve for

x^{3} + 1

x^{3} + x^{2} - 3 x - 1

f (x) = \frac{2 - ( 1 - 3 x )}{( 2 x - 5 )}

\frac{1}{x ^{2} + 1}

- 6 sin (3 x + \frac{π}{2})

x^{2} - 2 x - 8

What is the inverse of f(x)={\sqrt[3]{x-1},x>= 1} ?
The inverse of f(x)={\sqrt[3]{x-1},x>= 1} is x^3+1