What is the perpendicular y=-7/3 x+4,(-10,-5) ?

The perpendicular y=-7/3 x+4,(-10,-5) is y= 3/7 x-5/7

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perpendicular y=-7/3 x+4,(-10,-5)

perpendicular

y = - \frac{7}{3} x + 4, (- 10, - 5)

y = \frac{3}{7} x - \frac{5}{7}

Solution steps

Find the line

y = mx + b

perpendicular to

y = - \frac{7}{3} x + 4

that passes through

(- 10, - 5)

Find the slope of

y = - \frac{7}{3} x + 4 : m = - \frac{7}{3}

Compute the slope of the perpendicular line:

m_{p} = \frac{3}{7}

Find the line with slope m=

\frac{3}{7}

and passing through

(- 10, - 5) : y = \frac{3}{7} x - \frac{5}{7}

y = \frac{3}{7} x - \frac{5}{7}

f (x) = \frac{x - 3}{x + 4}

f (x) = \frac{1}{4} x - 2

f (- x) = \frac{x ^{2} + 5}{x}

f (x) = x^{2} - 5 x + 6

\frac{e ^{x} - e ^{- x}}{9}

What is the perpendicular y=-7/3 x+4,(-10,-5) ?
The perpendicular y=-7/3 x+4,(-10,-5) is y= 3/7 x-5/7