What is the critical f(x)=(x^3)/3-81x ?

The critical f(x)=(x^3)/3-81x is x=-9,x=9

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critical f(x)=(x^3)/3-81x

critical points

f (x) = \frac{x ^{3}}{3} - 81 x

x = - 9, x = 9

Solution steps

\frac{x ^{3}}{3} - 81 x

Find where

f^{'} (x)

is equal to zero or undefined

x = - 9, x = 9

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{3}}{3} - 81 x : - \infty < x < \infty

All critical points are in domain

x = - 9, x = 9

(2, 4), (- 3, - 9)

f (x) = sin (2 x)

\frac{2 x - 5}{7 x + 4}

\frac{x - 8}{x + 7}

lo g_{3} (x)

What is the critical f(x)=(x^3)/3-81x ?
The critical f(x)=(x^3)/3-81x is x=-9,x=9