What is the inverse of f(x)=((2x-3))/(x+1) ?

The inverse of f(x)=((2x-3))/(x+1) is (-3-x)/(x-2)

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inverse of f(x)=((2x-3))/(x+1)

inverse

f (x) = \frac{( 2 x - 3 )}{x + 1}

\frac{- 3 - x}{x - 2}

Solution steps

y = \frac{2 x - 3}{x + 1}

Replace

x

with

y

x = \frac{2 y - 3}{y + 1}

Solve for

y, x = \frac{2 y - 3}{y + 1}

\frac{- 3 - x}{x - 2}

sin (2) (x - \frac{π}{2}) + 1

\frac{7 e ^{x}}{7 + e ^{x}}

25 h^{2} + 28 h - 56

r (x) = \frac{x ( x - 18 ) ^{2}}{( x - 18 )}

(0, 4), (4, 0)

What is the inverse of f(x)=((2x-3))/(x+1) ?
The inverse of f(x)=((2x-3))/(x+1) is (-3-x)/(x-2)