What is the critical f(x)=x^{3/4}-9x^{1/4} ?

The critical f(x)=x^{3/4}-9x^{1/4} is x=0,x=9

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critical f(x)=x^{3/4}-9x^{1/4}

critical points

f (x) = x^{\frac{3}{4}} - 9 x^{\frac{1}{4}}

x = 0, x = 9

Solution steps

x^{\frac{3}{4}} - 9 x^{\frac{1}{4}}

Find where

f^{'} (x)

is equal to zero or undefined

x = 9, x = 0

Identify critical points not in

f (x)

domain

Domain of

x^{\frac{3}{4}} - 9 x^{\frac{1}{4}} : x \geq 0

All critical points are in domain

x = 0, x = 9

- x + 3 - 2

f (x) = x^{5} - 2

f (x) = \frac{( x + 3 )}{x ^{2} - 4 x + 3}

f (x) = x - 14

f (x) = 8 - 2 x

What is the critical f(x)=x^{3/4}-9x^{1/4} ?
The critical f(x)=x^{3/4}-9x^{1/4} is x=0,x=9