What is the domain of f(x)=((x+3))/(sqrt(x^2-4x+3)) ?

The domain of f(x)=((x+3))/(sqrt(x^2-4x+3)) is x 3

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domain of f(x)=((x+3))/(sqrt(x^2-4x+3))

domain

f (x) = \frac{( x + 3 )}{x ^{2} - 4 x + 3}

x < 1 or x > 3

Interval Notation

(- \infty, 1) \cup (3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 1 or x \geq 3

Find undefined (singularity) points:

x = 3, x = 1

Combine real regions and undefined points for final function domain

x < 1 or x > 3

f (x) = x - 14

f (x) = 8 - 2 x

f (x) = - 1

f (x) = \frac{- 4 x - 16}{x ^{2} - x - 20}

y = - \frac{4}{3} x - 8

What is the domain of f(x)=((x+3))/(sqrt(x^2-4x+3)) ?
The domain of f(x)=((x+3))/(sqrt(x^2-4x+3)) is x<1\lor x>3