What is the perpendicular y=-4/3 x-8 ?

The perpendicular y=-4/3 x-8 is y= 3/4 x+b

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perpendicular y=-4/3 x-8

perpendicular

y = - \frac{4}{3} x - 8

y = \frac{3}{4} x + b

Solution steps

Find the slope of

y = - \frac{4}{3} x - 8 : m = - \frac{4}{3}

Compute the slope of the perpendicular line:

m_{p} = \frac{3}{4}

Line with slope m=

\frac{3}{4} : y = \frac{3}{4} x + b

y = \frac{3}{4} x + b

2 x - 8 y = 1

h (x) = 7 x^{\frac{3}{5}}

(x + 3)^{3}

f (x) = (x - 2)^{2} - 9

y = (x + 7)^{3} - 2

What is the perpendicular y=-4/3 x-8 ?
The perpendicular y=-4/3 x-8 is y= 3/4 x+b