What is the inverse of f(x)=(x+18)/(x-16) ?

The inverse of f(x)=(x+18)/(x-16) is (18+16x)/(x-1)

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inverse of f(x)=(x+18)/(x-16)

inverse

f (x) = \frac{x + 18}{x - 16}

\frac{18 + 16 x}{x - 1}

Solution steps

y = \frac{x + 18}{x - 16}

Replace

x

with

y

x = \frac{y + 18}{y - 16}

Solve for

y, x = \frac{y + 18}{y - 16}

\frac{18 + 16 x}{x - 1}

\frac{x ^{2} + 3 x - 10}{x - 3}

\frac{x - 1}{x ^{3} + 4 x ^{2} + 12 x + 8}

f (x) = \frac{sec ( π x )}{2}

2 x^{6} + x^{8} + 3

3 x

What is the inverse of f(x)=(x+18)/(x-16) ?
The inverse of f(x)=(x+18)/(x-16) is (18+16x)/(x-1)