What is the domain of (4x^2+4x+1)/(2x^3+8x^2) ?

The domain of (4x^2+4x+1)/(2x^3+8x^2) is x 0

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domain of (4x^2+4x+1)/(2x^3+8x^2)

domain

\frac{4 x ^{2} + 4 x + 1}{2 x ^{3} + 8 x ^{2}}

x < - 4 or - 4 < x < 0 or x > 0

Interval Notation

(- \infty, - 4) \cup (- 4, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = - 4

The function domain

x < - 4 or - 4 < x < 0 or x > 0

(8, 1), (- 2, - 5)

f (x) = \frac{( 4 x ^{2} - 1 )}{∣ 2 x + 1 ∣}

x^{2} + 16

f (x) = \frac{5}{x - 9}

f (x) = arcsec (x)

What is the domain of (4x^2+4x+1)/(2x^3+8x^2) ?
The domain of (4x^2+4x+1)/(2x^3+8x^2) is x<-4\lor-4<x<0\lor x>0