What is the perpendicular y= x/4+7,(2,-2) ?

The perpendicular y= x/4+7,(2,-2) is y=-4x+6

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perpendicular y= x/4+7,(2,-2)

perpendicular

y = \frac{x}{4} + 7, (2, - 2)

y = - 4 x + 6

Solution steps

Find the line

y = mx + b

perpendicular to

y = \frac{x}{4} + 7

that passes through

(2, - 2)

Find the slope of

y = \frac{x}{4} + 7 : m = \frac{1}{4}

Compute the slope of the perpendicular line:

m_{p} = - 4

Find the line with slope m=

- 4

and passing through

(2, - 2) : y = - 4 x + 6

y = - 4 x + 6

f (x) = \frac{5 cos ( x )}{1 - sin ( x )}

y = \frac{x}{1 - ln ( x - 3 )}

\frac{x - 2}{5}

y = - \frac{3}{x + 4}

m = - \frac{4}{3} (0 - \frac{2}{5})

What is the perpendicular y= x/4+7,(2,-2) ?
The perpendicular y= x/4+7,(2,-2) is y=-4x+6