What is the domain of f(x)=(sqrt(3x))/(16x-33) ?

The domain of f(x)=(sqrt(3x))/(16x-33) is 0 33/16

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domain of f(x)=(sqrt(3x))/(16x-33)

domain

f (x) = \frac{3 x}{16 x - 33}

0 \leq x < \frac{33}{16} or x > \frac{33}{16}

Interval Notation

[0, \frac{33}{16}) \cup (\frac{33}{16}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = \frac{33}{16}

Combine real regions and undefined points for final function domain

0 \leq x < \frac{33}{16} or x > \frac{33}{16}

(4, 3), (- 2, 0)

(9, - 10), (- 3, 4)

f (x) = x^{4} - 6 x^{2}

(- 6, 2), (- 1, 3)

f (x) = \frac{x + 3}{3}

What is the domain of f(x)=(sqrt(3x))/(16x-33) ?
The domain of f(x)=(sqrt(3x))/(16x-33) is 0<= x< 33/16 \lor x> 33/16