What is the inverse of f(x)=0.2(x-1)^2-4 ?

The inverse of f(x)=0.2(x-1)^2-4 is sqrt(5)sqrt(x+4)+1,-sqrt(5)sqrt(x+4)+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=0.2(x-1)^2-4

inverse

f (x) = 0.2 (x - 1)^{2} - 4

5 x + 4 + 1, - 5 x + 4 + 1

Solution steps

y = 0.2 (x - 1)^{2} - 4

Replace

x

with

y

x = 0.2 (y - 1)^{2} - 4

Solve for

y, x = 0.2 (y - 1)^{2} - 4

5 x + 4 + 1, - 5 x + 4 + 1

(04) (0 - 3)

f (x) = 3 x e^{2 x}

f (t) = 2.3 cos (0.25 t)

f (x) = x^{2} + 4 x - 12

(5.6) (1.3)

What is the inverse of f(x)=0.2(x-1)^2-4 ?
The inverse of f(x)=0.2(x-1)^2-4 is sqrt(5)sqrt(x+4)+1,-sqrt(5)sqrt(x+4)+1