What is the domain of f(x)= 1/(sqrt(6+x)) ?

The domain of f(x)= 1/(sqrt(6+x)) is x>-6

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domain of f(x)= 1/(sqrt(6+x))

domain

f (x) = \frac{1}{6 + x}

x > - 6

Interval Notation

(- 6, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 6

Find undefined (singularity) points:

x = - 6

Combine real regions and undefined points for final function domain

x > - 6

f (x) = \frac{2}{x - 3}

f (x) = \frac{x - 6}{x ^{2} + 2}

f (x) = x^{2} - 8 x

f (x) = \frac{5}{2 - x}, x < 2

y = - \frac{5}{2} x + 6

What is the domain of f(x)= 1/(sqrt(6+x)) ?
The domain of f(x)= 1/(sqrt(6+x)) is x>-6