What is the perpendicular y=4x+6,(-8,10) ?

The perpendicular y=4x+6,(-8,10) is y=-1/4 x+8

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perpendicular y=4x+6,(-8,10)

perpendicular

y = 4 x + 6, (- 8, 10)

y = - \frac{1}{4} x + 8

Solution steps

Find the line

y = mx + b

perpendicular to

y = 4 x + 6

that passes through

(- 8, 10)

Find the slope of

y = 4 x + 6 : m = 4

Compute the slope of the perpendicular line:

m_{p} = - \frac{1}{4}

Find the line with slope m=

- \frac{1}{4}

and passing through

(- 8, 10) : y = - \frac{1}{4} x + 8

y = - \frac{1}{4} x + 8

1 + x^{2}

7 x - 12 y = 14

y = x^{2} - 3 x

f (x) = 28 x^{3} + \frac{12}{x}

f (x) = - 3 x^{2} + 30 x - 8

What is the perpendicular y=4x+6,(-8,10) ?
The perpendicular y=4x+6,(-8,10) is y=-1/4 x+8