What is the monotone sqrt(1+x^2) ?

The monotone sqrt(1+x^2) is Decreasing:-infinity <x<0,Increasing:0<x<infinity

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monotone sqrt(1+x^2)

monotone intervals

1 + x^{2}

Decreasing : - \infty < x < 0, Increasing : 0 < x < \infty

Solution steps

f^{'} (x) = \frac{x}{1 + x ^{2}}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Decreasing : - \infty < x < 0, Increasing : 0 < x < \infty

7 x - 12 y = 14

y = x^{2} - 3 x

f (x) = 28 x^{3} + \frac{12}{x}

f (x) = - 3 x^{2} + 30 x - 8

f (x) = x^{2} - 64

What is the monotone sqrt(1+x^2) ?
The monotone sqrt(1+x^2) is Decreasing:-infinity <x<0,Increasing:0<x<infinity