What is the shift f(x)=5sin(2/3 x-2/9 pi) ?

The shift f(x)=5sin(2/3 x-2/9 pi) is Phase: pi/3 , Vertical:0

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shift f(x)=5sin(2/3 x-2/9 pi)

shift

f (x) = 5 sin (\frac{2}{3} x - \frac{2}{9} π)

Phase : \frac{π}{3}, Vertical : 0

Solution steps

Simplify

5 sin (\frac{2}{3} x - \frac{2}{9} π) : 5 sin (\frac{2}{3} x - \frac{2 π}{9})

f (x) = 5 sin (\frac{2}{3} x - \frac{2 π}{9})

g (B x - C) = sin (\frac{2}{3} x - \frac{2 π}{9}), B = \frac{2}{3}, C = \frac{2 π}{9}, D = 0

Therefore, the phase shift

\frac{C}{B}

\frac{\frac{2 π}{9}}{\frac{2}{3}}

\frac{π}{3}

The vertical shift

D

0

0

y = (cos (3 x))^{x}

\frac{2 x ^{2} + 8 x - 24}{x ^{2} + x - 12}

f (x) = \frac{12}{x} - 18

f (x) = \frac{1}{x ^{2} - 1}

f (x) = 2 x^{3} - 6 x^{2} + 30

What is the shift f(x)=5sin(2/3 x-2/9 pi) ?
The shift f(x)=5sin(2/3 x-2/9 pi) is Phase: pi/3 , Vertical:0