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midpoint
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inverse of f(x)=\sqrt[5]{2(x-8)+7}inverse inflection (x^2-7)^3inflection points domain of f(x)= 4/(3+x)domain symmetry y=(x+2)^2symmetry domain of x^3-6x^2-15x+3domain
Frequently Asked Questions (FAQ)
What is the midpoint (-3,-2),(2,3) ?
The midpoint (-3,-2),(2,3) is (-1/2 , 1/2)