What is the inverse of f(x)=y^2-4y+3 ?

The inverse of f(x)=y^2-4y+3 is 2+sqrt(y+1),2-sqrt(y+1)

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inverse of f(x)=y^2-4y+3

inverse

f (x) = y^{2} - 4 y + 3

2 + y + 1, 2 - y + 1

Solution steps

x = y^{2} - 4 y + 3

Replace

y

with

x

y = x^{2} - 4 x + 3

Solve for

x, y = x^{2} - 4 x + 3

2 + y + 1, 2 - y + 1

y = - 3 x - 1

3 cos (x)

\frac{x ^{2} - 1}{x ^{3}}

f (x) = - \frac{2}{5} x^{6} + 5 x^{4}

f (x) = x 9 - x

What is the inverse of f(x)=y^2-4y+3 ?
The inverse of f(x)=y^2-4y+3 is 2+sqrt(y+1),2-sqrt(y+1)