What is the asymptotes of f(x)=(2x-4)/(2x^2-1) ?

The asymptotes of f(x)=(2x-4)/(2x^2-1) is Vertical: x=-1/(sqrt(2)),x= 1/(sqrt(2)),Horizontal: y=0

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asymptotes of f(x)=(2x-4)/(2x^2-1)

asymptotes

f (x) = \frac{2 x - 4}{2 x ^{2} - 1}

Vertical : x = - \frac{1}{2}, x = \frac{1}{2}, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{2 x - 4}{2 x ^{2} - 1} : x = - \frac{1}{2}, x = \frac{1}{2}

Horizontal Asymptotes of

\frac{2 x - 4}{2 x ^{2} - 1} : y = 0

Slant Asymptotes of

\frac{2 x - 4}{2 x ^{2} - 1} :

None

Vertical : x = - \frac{1}{2}, x = \frac{1}{2}, Horizontal : y = 0

- 4 + (x - 2)^{2}

m = - 4 (0.8)

(1.2) (6.8)

(- 3.36, - 3.355), (0, 0)

81 - x^{2}

What is the asymptotes of f(x)=(2x-4)/(2x^2-1) ?
The asymptotes of f(x)=(2x-4)/(2x^2-1) is Vertical: x=-1/(sqrt(2)),x= 1/(sqrt(2)),Horizontal: y=0