What is the domain of f(x)=sqrt((x-1)/(x+1)) ?

The domain of f(x)=sqrt((x-1)/(x+1)) is x = 1

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domain of f(x)=sqrt((x-1)/(x+1))

domain

f (x) = \frac{x - 1}{x + 1}

x < - 1 or x \geq 1

Interval Notation

(- \infty, - 1) \cup [1, \infty)

Solution steps

Find non-negative values for radicals:

x < - 1 or x \geq 1

Find undefined (singularity) points:

x = - 1

Combine real regions and undefined points for final function domain

x < - 1 or x \geq 1

y = - 2 (x + 1)^{2} + 3

f (x) = 3 - (x - 4)^{2}

f (x) = - 2 (x - 1)^{2} - 4

f (x) = \frac{3}{4} x + 2

What is the domain of f(x)=sqrt((x-1)/(x+1)) ?
The domain of f(x)=sqrt((x-1)/(x+1)) is x<-1\lor x>= 1