What is the inverse of f(x)=3-(x-4)^2 ?

The inverse of f(x)=3-(x-4)^2 is sqrt(-x+3)+4,-sqrt(-x+3)+4

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inverse of f(x)=3-(x-4)^2

inverse

f (x) = 3 - (x - 4)^{2}

- x + 3 + 4, - - x + 3 + 4

Solution steps

y = 3 - (x - 4)^{2}

Replace

x

with

y

x = 3 - (y - 4)^{2}

Solve for

y, x = 3 - (y - 4)^{2}

- x + 3 + 4, - - x + 3 + 4

f (x) = - 2 (x - 1)^{2} - 4

f (x) = \frac{3}{4} x + 2

10 - x

f (x) = \frac{( x - 3 )}{x ^{2} - 4 x - 12}

What is the inverse of f(x)=3-(x-4)^2 ?
The inverse of f(x)=3-(x-4)^2 is sqrt(-x+3)+4,-sqrt(-x+3)+4