What is the domain of f(x)=((x-3))/(x^2-4x-12) ?

The domain of f(x)=((x-3))/(x^2-4x-12) is x 6

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domain of f(x)=((x-3))/(x^2-4x-12)

domain

f (x) = \frac{( x - 3 )}{x ^{2} - 4 x - 12}

x < - 2 or - 2 < x < 6 or x > 6

Interval Notation

(- \infty, - 2) \cup (- 2, 6) \cup (6, \infty)

Solution steps

Find undefined (singularity) points:

x = 6, x = - 2

The function domain

x < - 2 or - 2 < x < 6 or x > 6

f (x) = \frac{1}{4 x + 3}

- 6 cos (4 x - \frac{π}{2})

(0, 0), (\frac{3}{2}, \frac{1}{2})

f (x) = \frac{x - 5}{25 x - x ^{3}}

What is the domain of f(x)=((x-3))/(x^2-4x-12) ?
The domain of f(x)=((x-3))/(x^2-4x-12) is x<-2\lor-2<x<6\lor x>6