What is the domain of f(x)= 1/(sqrt(4x+3)) ?

The domain of f(x)= 1/(sqrt(4x+3)) is x>-3/4

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domain of f(x)= 1/(sqrt(4x+3))

domain

f (x) = \frac{1}{4 x + 3}

x > - \frac{3}{4}

Interval Notation

(- \frac{3}{4}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{3}{4}

Find undefined (singularity) points:

x = - \frac{3}{4}

Combine real regions and undefined points for final function domain

x > - \frac{3}{4}

- 6 cos (4 x - \frac{π}{2})

(0, 0), (\frac{3}{2}, \frac{1}{2})

f (x) = \frac{x - 5}{25 x - x ^{3}}

3 x - 4 y = 10

(- 3, 5), (1, - 9)

What is the domain of f(x)= 1/(sqrt(4x+3)) ?
The domain of f(x)= 1/(sqrt(4x+3)) is x>-3/4