What is the extreme f(x)=-x^3-9x^2-24x-1 ?

The extreme f(x)=-x^3-9x^2-24x-1 is Minimum(-4,15),Maximum(-2,19)

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extreme f(x)=-x^3-9x^2-24x-1

extreme points

f (x) = - x^{3} - 9 x^{2} - 24 x - 1

Minimum (- 4, 15), Maximum (- 2, 19)

Solution steps

f^{'} (x) = - 3 x^{2} - 18 x - 24

Find intervals:

Decreasing

: - \infty < x < - 4,

Increasing

: - 4 < x < - 2,

Decreasing

: - 2 < x < \infty

Plug

x = - 4

into

- x^{3} - 9 x^{2} - 24 x - 1 : 15

Minimum (- 4, 15)

Plug

x = - 2

into

- x^{3} - 9 x^{2} - 24 x - 1 : 19

Maximum (- 2, 19)

Minimum (- 4, 15), Maximum (- 2, 19)

f (x) = \frac{( x ^{2} + 20 )}{5 ( x - 2 ) ^{2}}

\frac{x ^{2} + x - 6}{x ^{3} - 1}

f (x) = \frac{x - 9}{x + 9}

f (x) = 3 + (2 + x)^{\frac{1}{2}}

(1.9) a^{8}

What is the extreme f(x)=-x^3-9x^2-24x-1 ?
The extreme f(x)=-x^3-9x^2-24x-1 is Minimum(-4,15),Maximum(-2,19)