What is the range of f(x)=3+(2+x)^{1/2} ?

The range of f(x)=3+(2+x)^{1/2} is f(x)>= 3

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range of f(x)=3+(2+x)^{1/2}

range

f (x) = 3 + (2 + x)^{\frac{1}{2}}

f (x) \geq 3

Interval Notation

[3, \infty)

Solution steps

The range of an radical function of the form

c a x + b + k

f (x) \geq k

k = 3

f (x) \geq 3

(1.9) a^{8}

f (x) = \frac{2 x - 3}{5 x - 1}

f (x) = \frac{x}{7}

f (x) = \frac{( x + 1 )}{3}

f (x) = - 0.2 t^{2} + 1.6 t + 98.9

What is the range of f(x)=3+(2+x)^{1/2} ?
The range of f(x)=3+(2+x)^{1/2} is f(x)>= 3