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Popular >

range of sin(-2x)

Solution

range

sin (- 2 x)

Solution

- 1 \leq f (x) \leq 1

+1

Interval Notation

[- 1, 1]

Solution steps

The range of the basic

sin

function is

- 1 \leq sin (- 2 x) \leq 1

- 1 \leq sin (- 2 x) \leq 1

Therefore the range is

- 1 \leq f (x) \leq 1

Popular Examples

domain of f(x)=(2x+3)sqrt(x^2+8)domain

f (x) = (2 x + 3) x^{2} + 8

domain of (x+9)/2 domain

\frac{x + 9}{2}

domain of f(x)=sqrt(x^2+25)domain

f (x) = x^{2} + 25

inflection f(x)=3x^2-x^3 inflection points

f (x) = 3 x^{2} - x^{3}

asymptotes of f(x)=3x+2-log_{e}(x^2-1)asymptotes

f (x) = 3 x + 2 - lo g_{e} (x^{2} - 1)

Frequently Asked Questions (FAQ)

What is the range of sin(-2x) ?
The range of sin(-2x) is -1<= f(x)<= 1