What is the domain of f(x)=ln((x^2)/(x-1)) ?

The domain of f(x)=ln((x^2)/(x-1)) is x>1

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domain of f(x)=ln((x^2)/(x-1))

domain

f (x) = ln (\frac{x ^{2}}{x - 1})

x > 1

Interval Notation

(1, \infty)

Solution steps

Find positive values for logs:

x > 1

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

x > 1

\frac{1}{x + 15}

f (x) = \frac{ln ( x )}{x}

(1992, 61.6), (1997, 64)

- 3 x + 2 y = 6

(- 6, 6), (- 3, 3)

What is the domain of f(x)=ln((x^2)/(x-1)) ?
The domain of f(x)=ln((x^2)/(x-1)) is x>1