What is the domain of f(x)=(-4)/(x^2-1) ?

The domain of f(x)=(-4)/(x^2-1) is x 1

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domain of f(x)=(-4)/(x^2-1)

domain

f (x) = \frac{- 4}{x ^{2} - 1}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

y = 3 x + 1, (- 3, 6)

f (x) = \frac{- 5 x - 15}{2 x ^{2} + 5 x - 3}

f (x) = \frac{3}{2} x - 6

f (x) = \frac{6}{x - 9}

2 x - 5 y = 0

What is the domain of f(x)=(-4)/(x^2-1) ?
The domain of f(x)=(-4)/(x^2-1) is x<-1\lor-1<x<1\lor x>1