What is the domain of 8/((x-1)(x+2)) ?

The domain of 8/((x-1)(x+2)) is x 1

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domain of 8/((x-1)(x+2))

domain

\frac{8}{( x - 1 ) ( x + 2 )}

x < - 2 or - 2 < x < 1 or x > 1

Interval Notation

(- \infty, - 2) \cup (- 2, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 2

The function domain

x < - 2 or - 2 < x < 1 or x > 1

\frac{x}{x ^{2} + 4}

y = tan (x)

(8, 10), (- 2, 14)

f (x) = x^{2} - 2 x

x

What is the domain of 8/((x-1)(x+2)) ?
The domain of 8/((x-1)(x+2)) is x<-2\lor-2<x<1\lor x>1