What is the domain of f(x)=(x^2)/(x+9) ?

The domain of f(x)=(x^2)/(x+9) is x -9

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domain of f(x)=(x^2)/(x+9)

domain

f (x) = \frac{x ^{2}}{x + 9}

x < - 9 or x > - 9

Interval Notation

(- \infty, - 9) \cup (- 9, \infty)

Solution steps

Find undefined (singularity) points:

x = - 9

The function domain

x < - 9 or x > - 9

f (x) = \frac{x + 3}{2 - 3 x}

f (x) = 10 x + 1

f (x) = \frac{x ^{2} + x - 6}{3 x + 3}

f (x) = x^{4} - 4 x^{3} + 6

What is the domain of f(x)=(x^2)/(x+9) ?
The domain of f(x)=(x^2)/(x+9) is x<-9\lor x>-9