What is the critical f(x)=(x^2-8x-8)/(x-2) ?

The critical f(x)=(x^2-8x-8)/(x-2) is None

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critical f(x)=(x^2-8x-8)/(x-2)

critical points

f (x) = \frac{x ^{2} - 8 x - 8}{x - 2}

None

Solution steps

\frac{x ^{2} - 8 x - 8}{x - 2}

Find where

f^{'} (x)

is equal to zero or undefined

x = 2

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} - 8 x - 8}{x - 2} : x < 2 or x > 2

\frac{x ^{2} - 8 x - 8}{x - 2}

is not defined at

x = 2

, therefore:

None

- 3 x + 7

f (x) = 4 x + 5 + 8

f (x) = 2 e^{x + 2} - 3

f (x) = 7 - 8 x^{2}

(x - 5)^{2} - 4

What is the critical f(x)=(x^2-8x-8)/(x-2) ?
The critical f(x)=(x^2-8x-8)/(x-2) is None