What is the domain of f(x)=sqrt((x+1)) ?

The domain of f(x)=sqrt((x+1)) is x>=-1

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domain of f(x)=sqrt((x+1))

domain

f (x) = (x + 1)

x \geq - 1

Interval Notation

[- 1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

The function domain

x \geq - 1

5 x + 6 y = - 24

y = x

f (x) = - x + 2

f (x) = 2 x^{3} + 2 x^{2} - 18 x - 18

(- 1, - i), (2, i 2)

What is the domain of f(x)=sqrt((x+1)) ?
The domain of f(x)=sqrt((x+1)) is x>=-1