What is the range of f(x)=-sqrt(x+2) ?

The range of f(x)=-sqrt(x+2) is f(x)<= 0

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range of f(x)=-sqrt(x+2)

range

f (x) = - x + 2

f (x) \leq 0

Interval Notation

(- \infty, 0]

Solution steps

The range of an radical function of the form

- c a x + b + k

f (x) \leq k

k = 0

f (x) \leq 0

f (x) = 2 x^{3} + 2 x^{2} - 18 x - 18

(- 1, - i), (2, i 2)

f (x) = x^{2} - 6 x

f (x) = (\frac{3}{2})^{x} - 2

f (x) = - 2 (3)^{x}